probability - Rolling $2$ dice: NOT using $36$ as the base

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I apologize for such a simple question. It has been a while since I took math classes. When you roll $2$ dice, there are $36$ possibilities. However, there are only $21$ combinations, if order do
probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
Solved When two balanced dice are roled, 36 equally likely
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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probability - Rolling $2$ dice: NOT using $36$ as the base
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